Match the intermediates given in Column $-I$ with their probable structure in Column $-II$.
Column $-I$ Column $-II$ $A$. Free radical $1$. Trigonal planar $B$. Carbocation $2$. Pyramidal $C$. Carbanion $3$. Linear
| Column $-I$ | Column $-II$ |
|---|---|
| $A$. Free radical | $1$. Trigonal planar |
| $B$. Carbocation | $2$. Pyramidal |
| $C$. Carbanion | $3$. Linear |
(A-1, B-1, C-2) $A-1, B-1, C-2$
$A$. Free radicals are formed by homolytic cleavage and they are trigonal planar.
$B$. Carbocations are formed by heterolytic cleavage,where the central carbon is $sp^2$ hybridized,resulting in a trigonal planar geometry.
$C$. Carbanions have a lone pair of electrons on the central carbon,which is $sp^3$ hybridized,resulting in a pyramidal geometry.
$A$. Free radicals are formed by homolytic cleavage and they are trigonal planar.
$B$. Carbocations are formed by heterolytic cleavage,where the central carbon is $sp^2$ hybridized,resulting in a trigonal planar geometry.
$C$. Carbanions have a lone pair of electrons on the central carbon,which is $sp^3$ hybridized,resulting in a pyramidal geometry.
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