Match the List-$I$ with List-$II$:
$A$. Carbocation $I$. Species that can supply a pair of electrons.
$B$. Carbon free radical $II$. Species that can receive a pair of electrons.
$C$. Nucleophile $III$. $sp^2$ hybridized carbon with empty $p$-orbital.
$D$. Electrophile $IV$. $sp^2/sp^3$ hybridized carbon with one unpaired electron.

Choose the correct answer from the options given below:

  • A
    $A-IV, B-II, C-III, D-I$
  • B
    $A-II, B-III, C-I, D-IV$
  • C
    $A-III, B-IV, C-II, D-I$
  • D
    $A-III, B-IV, C-I, D-II$

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With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

Which of the following compounds gives the most stable carbocation upon dehydrogenation?

How many carbon-hydrogen bond orbitals are available for overlap with the vacant $p$-orbital in ethyl carbocation?

Arrange the following carbocations in decreasing order of stability.

The stability of the following carbocations follows the order:
$I. (CH_3)_3C^{\oplus}$
$II. (CH_3)_2C^{\oplus}(OCH_3)$
$III. CH_3CH_2CH_2CH_2^{\oplus}$
$IV. CH_3CH^{\oplus}CH_2CH_3$

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