With a change in hybridisation of the carbon | vedclass

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Question

(C) The stability of carbanions increases with an increase in the $s-$character of the hybrid orbitals of the carbon atom bearing the negative charge.

Vedclass · Accepted Answer

$sp^3 < sp^2 < sp$

Vedclass · Answer

(C) The stability of carbanions increases with an increase in the $s-$character of the hybrid orbitals of the carbon atom bearing the negative charge.This is because a higher $s-$character makes the orbital more electronegative,which better stabilizes the negative charge.The $s-$character in different hybridizations is: $sp$ $(50\%)$,$sp^2$ $(33.3\%)$,and $sp^3$ $(25\%)$.Therefore,the correct order of stability is: $sp^3 < sp^2 < sp$.

With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

Similar Questions

The correct stability order for the following carbocations is:

The stability of the following carbanions is in the order of:

Identify the most stable free radical from the following.

In the above reaction,the left-hand side and right-hand side rings are named as '$A$' and '$B$' respectively. They undergo ring expansion. The correct statement for this process is:

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