With a change in hybridisation of the carbon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The stability of carbanions increases with an increase in the $s-$character of the hybrid orbitals of the carbon atom bearing the negative charge.

Vedclass · Accepted Answer

$sp^3 < sp^2 < sp$

Vedclass · Answer

(C) The stability of carbanions increases with an increase in the $s-$character of the hybrid orbitals of the carbon atom bearing the negative charge.This is because a higher $s-$character makes the orbital more electronegative,which better stabilizes the negative charge.The $s-$character in different hybridizations is: $sp$ $(50\%)$,$sp^2$ $(33.3\%)$,and $sp^3$ $(25\%)$.Therefore,the correct order of stability is: $sp^3 < sp^2 < sp$.

With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

Similar Questions

The number of hyperconjugation structures involved to stabilize the carbocation formed in the above reaction is $.............$.

The order of stability of the following carbocations is:
$I$. $CH_2 = CH - CH_2^+$
$II$. $CH_3 - CH_2 - CH_2^+$
$III$. $C_6H_5CH_2^+$

The shape of a carbocation is:

Identify the correct order of stability for carbocations.

What is the shape of the methyl carbocation,$\overset{\oplus}{C}H_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module