Match the List-I with List-II:

L | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state. Configuration: $[Ar] 3d^8 4s^2$. Due to strong field ligand $CO$,electrons pair up. Hybridization: $

Vedclass · Accepted Answer

$A-III, B-II, C-I, D-IV$

Vedclass · Answer

(A) $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state. Configuration: $[Ar] 3d^8 4s^2$. Due to strong field ligand $CO$,electrons pair up. Hybridization: $sp^3$. Shape: Tetrahedral. Magnetic moment: $0 \ BM$ (Diamagnetic). Matches $III$.
$(B)$ $[Ni(CN)_4]^{2-}$: $Ni$ is in $+2$ oxidation state. Configuration: $[Ar] 3d^8$. Due to strong field ligand $CN^-$,electrons pair up. Hybridization: $dsp^2$. Shape: Square planar. Magnetic moment: $0 \ BM$ (Diamagnetic). Matches $II$.
$(C)$ $[NiCl_4]^{2-}$: $Ni$ is in $+2$ oxidation state. Configuration: $[Ar] 3d^8$. Weak field ligand $Cl^-$. Hybridization: $sp^3$. Shape: Tetrahedral. Two unpaired electrons,$\mu = \sqrt{n(n+2)} = \sqrt{2(4)} = \sqrt{8} \approx 2.8 \ BM$. Matches $I$.
$(D)$ $[MnBr_4]^{2-}$: $Mn$ is in $+2$ oxidation state. Configuration: $[Ar] 3d^5$. Weak field ligand $Br^-$. Hybridization: $sp^3$. Shape: Tetrahedral. Five unpaired electrons,$\mu = \sqrt{5(7)} = \sqrt{35} \approx 5.9 \ BM$. Matches $IV$.
Therefore,the correct matching is $A-III, B-II, C-I, D-IV$.

List-$I$ (Complex/Species)	List-$II$ (Shape and magnetic moment)
$A$. $[Ni(CO)_4]$	$I$. Tetrahedral,$2.8 \ BM$
$B$. $[Ni(CN)_4]^{2-}$	$II$. Square planar,$0 \ BM$
$C$. $[NiCl_4]^{2-}$	$III$. Tetrahedral,$0 \ BM$
$D$. $[MnBr_4]^{2-}$	$IV$. Tetrahedral,$5.9 \ BM$

List-$I$ (Molecules/ion)	List-$II$ (Hybridisation of central atom)
$A. PF_5$	$I. dsp^2$
$B. SF_6$	$II. sp^3d$
$C. Ni(CO)_4$	$III. sp^3d^2$
$D. [PtCl_4]^{2-}$	$IV. sp^3$

List-$I$	List-$II$
$(1)$ $dsp^2$	$(A)$ $BrF_5$
$(2)$ $sp^3d^2$	$(B)$ $[Co(NH_3)_6]^{3+}$
$(3)$ $sp^3d$	$(C)$ $[PtCl_4]^{2-}$
$(4)$ $d^2sp^3$	$(D)$ $PCl_5$

Similar Questions

What is the geometry of $[Ni(CO)_4]$?

Which of the following statements is incorrect?

Which of the following complexes does not involve inner orbital hybridization?

Match the List-$I$ with List-$II$
List-$I$ (Molecules/ion) List-$II$ (Hybridisation of central atom)
$A. PF_5$ $I. dsp^2$
$B. SF_6$ $II. sp^3d$
$C. Ni(CO)_4$ $III. sp^3d^2$
$D. [PtCl_4]^{2-}$ $IV. sp^3$
Choose the correct answer from the options given below $:$

Match the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$.

List-$I$ List-$II$

$(1)$ $dsp^2$ $(A)$ $BrF_5$

$(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$

$(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$

$(4)$ $d^2sp^3$ $(D)$ $PCl_5$

Vedclass Test Series

Exam Paper Generator

Online Exam Module