Match the List-I with List-II. The correct ma | vedclass

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(B) The Boltzmann constant $k_B$ relates energy to temperature: $E = k_B T$. Thus, $[k_B] = [	ext{Energy}] / [	ext{Temperature}] = [ML^2T^{-2}] / [K

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$A-III, B-II, C-I, D-IV$

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(B) The Boltzmann constant $k_B$ relates energy to temperature: $E = k_B T$. Thus, $[k_B] = [	ext{Energy}] / [	ext{Temperature}] = [ML^2T^{-2}] / [K] = [ML^2T^{-2}K^{-1}]$. This matches $III$.
$(B)$ From Stokes' law, $F = 6\pi \eta r v$. The dimensions of viscosity $\eta$ are $[F] / ([L][LT^{-1}]) = [MLT^{-2}] / [L^2T^{-1}] = [ML^{-1}T^{-1}]$. This matches $II$.
$(C)$ Water equivalent is the mass of water that absorbs the same amount of heat as the body for the same temperature change. Its dimension is $[M]$. However, in the given options, $[ML^0T^0]$ is the closest representation of mass. This matches $I$.
$(D)$ From the heat conduction formula $Q/t = KA(	heta_1 - 	heta_2)/l$, the coefficient of thermal conductivity $K = (Q \cdot l) / (A \cdot t \cdot \Delta	heta)$. Dimensions: $[ML^2T^{-2} \cdot L] / [L^2 \cdot T \cdot K] = [MLT^{-3}K^{-1}]$. This matches $IV$.
Therefore, the correct sequence is $A-III, B-II, C-I, D-IV$.

List-$I$	List-$II$
$A$. Boltzmann constant	$I$. $[ML^0T^0]$
$B$. Coefficient of viscosity	$II$. $[ML^{-1}T^{-1}]$
$C$. Water equivalent	$III$. $[ML^2T^{-2}K^{-1}]$
$D$. Coefficient of thermal conductivity	$IV$. $[MLT^{-3}K^{-1}]$

List-$I$	List-$II$
$(i)$ Curie	$(A)$ $MLT^{-2}$
$(ii)$ Light year	$(B)$ $M$
$(iii)$ Dielectric strength	$(C)$ Dimensionless
$(iv)$ Atomic weight	$(D)$ $T$
$(v)$ Decibel	$(E)$ $ML^2T^{-2}$
	$(F)$ $MT^{-3}$
	$(G)$ $T^{-1}$
	$(H)$ $L$
	$(I)$ $MLT^{-3}I^{-1}$
	$(J)$ $LT^{-1}$

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