Match the List-I with List-II:List-IList-IIA. | vedclass

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(B) . Finkelstein reaction involves the exchange of halogen atoms, typically using $NaI$ in acetone to prepare alkyl iodides.$B$. Swarts reaction is u

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$A-III, B-I, C-IV, D-II$

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(B) . Finkelstein reaction involves the exchange of halogen atoms, typically using $NaI$ in acetone to prepare alkyl iodides.$B$. Swarts reaction is used to prepare alkyl fluorides by treating alkyl chlorides or bromides with metallic fluorides like $SbF_3$ or $AgF$.$C$. Sandmeyer's reaction involves the conversion of diazonium salts into aryl halides using copper$(I)$ salts like $Cu_2Cl_2$.$D$. Fittig reaction involves the coupling of two aryl halide molecules in the presence of $Na$ metal and dry ether to form diaryls.Therefore, the correct matching is $A-III, B-I, C-IV, D-II$.

List-$I$	List-$II$
$A$. Finkelstein reaction	$I$. $SbF_3$
$B$. Swarts reaction	$II$. $Na$, dry ether
$C$. Sandmeyer's reaction	$III$. $NaI$
$D$. Fittig reaction	$IV$. $Cu_2Cl_2$

Column-$I$ (Reactants)	Column-$II$ (Name)
$A$. $R-X + NaI \xrightarrow{\text{dry acetone}} R-I + NaX$	$i$. Electrophilic addition
$B$. $H_3C-Br + AgF \to H_3C-F + AgBr$	$ii$. Finkelstein reaction
$C$. $H_3C-CH_3 + Cl_2 \xrightarrow{hv} H_3C-CH_2Cl + HCl$	$iii$. Swarts reaction
$D$. $CH_2=CH_2 + Br_2 \to BrCH_2-CH_2Br$	$iv$. Free radical substitution

Match the List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. Finkelstein reaction $I$. $SbF_3$
$B$. Swarts reaction $II$. $Na$, dry ether
$C$. Sandmeyer's reaction $III$. $NaI$
$D$. Fittig reaction $IV$. $Cu_2Cl_2$

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Match the List-$I$ with List-$II$:List-$I$List-$II$$A$. Finkelstein reaction$I$. $SbF_3$$B$. Swarts reaction$II$. $Na$, dry ether$C$. Sandmeyer's reaction$III$. $NaI$$D$. Fittig reaction$IV$. $Cu_2Cl_2$Choose the correct answer from the options given below: