(A) The correct matching is:$A$. $Nylon$ $6,6$ is a polyamide formed from $Adipic$ $acid$ and $Hexamethylenediamine$ $(v)$.$B$. $Terylene$ (also known

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(A) The correct matching is:$A$. $Nylon$ $6,6$ is a polyamide formed from $Adipic$ $acid$ and $Hexamethylenediamine$ $(v)$.$B$. $Terylene$ (also known as $Dacron$) is a polyester formed from $Ethylene$ $glycol$ and $Terephthalic$ $acid$ $(i)$.$C$. $Buna-S$ is a copolymer of $1,3-Butadiene$ and $Styrene$ $(ii)$.$D$. $Neoprene$ is a polymer of $Chloroprene$ $(iii)$.Therefore,the correct sequence for $A, B, C, D$ is $(v, i, ii, iii)$.

Class 12 Chemistry Polymers Composition, Properties and Uses of Polymer

Easy

Match the polymers in List-$I$ with their monomers in List-$II$ and select the correct match:
List-$I$ List-$II$
$A$. $Nylon$ $6,6$ $i$. $Ethylene$ $glycol$ and $Terephthalic$ $acid$
$B$. $Terylene$ $ii$. $1,3-Butadiene$ and $Styrene$
$C$. $Buna-S$ $iii$. $Chloroprene$
$D$. $Neoprene$ $iv$. $Acrylonitrile$
$v$. $Adipic$ $acid$ and $Hexamethylenediamine$

The correct match is:

List-$I$	List-$II$
$A$. $Nylon$ $6,6$	$i$. $Ethylene$ $glycol$ and $Terephthalic$ $acid$
$B$. $Terylene$	$ii$. $1,3-Butadiene$ and $Styrene$
$C$. $Buna-S$	$iii$. $Chloroprene$
$D$. $Neoprene$	$iv$. $Acrylonitrile$
	$v$. $Adipic$ $acid$ and $Hexamethylenediamine$