The molecular shapes of XeF_3^+ and SNF_3 spe | vedclass

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(A) For $XeF_3^+$: The central atom $Xe$ has $8$ valence electrons. $XeF_3^+$ has $8 - 3 + 1 = 6$ electrons,which corresponds to $3$ bond pairs and $2

Vedclass · Accepted Answer

$T$-shaped,Tetrahedral

Vedclass · Answer

(A) For $XeF_3^+$: The central atom $Xe$ has $8$ valence electrons. $XeF_3^+$ has $8 - 3 + 1 = 6$ electrons,which corresponds to $3$ bond pairs and $2$ lone pairs. The steric number is $5$,indicating $sp^3d$ hybridization. With $2$ lone pairs in the equatorial positions,the shape is $T$-shaped.For $SNF_3$: The central atom $S$ is bonded to $N$ (triple bond) and $3$ $F$ atoms (single bonds). The total number of electron pairs around $S$ is $4$ ($1$ triple bond + $3$ single bonds). The steric number is $4$,indicating $sp^3$ hybridization. The geometry is tetrahedral.

The molecular shapes of $XeF_3^+$ and $SNF_3$ species are respectively:

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