A mother tells her son,"Five years ago,I was | vedclass

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Question

(C) Let the present age of the mother be $x$ years and the present age of the son be $y$ years.Case $1$: Five years ago,the mother's age was $(x - 5)$

Vedclass · Accepted Answer

$x - 5y + 20 = 0$ and $x - 2y - 10 = 0$

Vedclass · Answer

(C) Let the present age of the mother be $x$ years and the present age of the son be $y$ years.Case $1$: Five years ago,the mother's age was $(x - 5)$ and the son's age was $(y - 5)$.According to the problem: $(x - 5) = 5(y - 5)$$x - 5 = 5y - 25$$x - 5y + 20 = 0$Case $2$: After ten years,the mother's age will be $(x + 10)$ and the son's age will be $(y + 10)$.According to the problem: $(x + 10) = 2(y + 10)$$x + 10 = 2y + 20$$x - 2y - 10 = 0$Thus,the pair of linear equations is $x - 5y + 20 = 0$ and $x - 2y - 10 = 0$.

$A$ mother tells her son,"Five years ago,$I$ was five times as old as you were. After ten years,$I$ will be two times as old as you will be." Represent this situation as a pair of linear equations in two variables.

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