Nodal planes of $\pi$-bond$(s)$ in $CH_2=C=C=CH_2$ are located in

  • A
    all are in molecular plane
  • B
    two in molecular plane and one in a plane perpendicular to molecular plane which contains $C-C$ $\sigma$-bond
  • C
    one in molecular plane and two in plane perpendicular to molecular plane which contains $C-C$ $\sigma$-bonds
  • D
    two in molecular plane and one in a plane perpendicular to molecular plane which bisects $C-C$ $\sigma$-bonds at right angle

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Similar Questions

How is the $F_2$ molecule formed?

Determine the number of $\sigma$ and $\pi$ bonds in the following molecules:
$(i)$ $O_2$
$(ii)$ $N_2$
$(iii)$ $C_6H_6$ (Benzene)
$(iv)$ $O_3$ (Ozone)

Which one is stronger,$\sigma$ bond or $\pi$ bond? Why?

In a $\sigma$ bond,

Considering the $X$-axis as the internuclear axis,which of the following will not form a sigma $(\sigma)$ bond and why?

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