The number of divisors of n = 38808 (excludin | vedclass

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(A) First,find the prime factorization of $n = 38808$.$38808 = 8 	imes 4851$$38808 = 2^3 	imes 9 	imes 539$$38808 = 2^3 	imes 3^2 	imes 7^2 	ime

Vedclass · Accepted Answer

$70$

Vedclass · Answer

(A) First,find the prime factorization of $n = 38808$.$38808 = 8 	imes 4851$$38808 = 2^3 	imes 9 	imes 539$$38808 = 2^3 	imes 3^2 	imes 7^2 	imes 11^1$The total number of divisors is given by the product of (exponent + $1$) for each prime factor:Total divisors $= (3 + 1)(2 + 1)(2 + 1)(1 + 1) = 4 	imes 3 	imes 3 	imes 2 = 72$.Since we must exclude the divisors $1$ and $n$ $(38808)$,the required number of divisors is:$72 - 2 = 70$.

The number of divisors of $n = 38808$ (excluding $1$ and $n$) is

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