Observe the following lists. Then the correct match for List-$I$ from List-$II$ is:
List-$I$ List-$II$ $(A)$ $[\mathbf{a} \mathbf{b} \mathbf{c}]$ $1. |\mathbf{a}||\mathbf{b}|\cos(\mathbf{a}, \mathbf{b})$ $(B)$ $(\mathbf{c} \times \mathbf{a}) \times \mathbf{b}$ $2. (\mathbf{a} \cdot \mathbf{c})\mathbf{b} - (\mathbf{a} \cdot \mathbf{b})\mathbf{c}$ $(C)$ $\mathbf{a} \times (\mathbf{b} \times \mathbf{c})$ $3. \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})$ $(D)$ $\mathbf{a} \cdot \mathbf{b}$ $4. |\mathbf{a}||\mathbf{b}|$ $5. (\mathbf{b} \cdot \mathbf{c})\mathbf{a} - (\mathbf{a} \cdot \mathbf{b})\mathbf{c}$
| List-$I$ | List-$II$ |
| $(A)$ $[\mathbf{a} \mathbf{b} \mathbf{c}]$ | $1. |\mathbf{a}||\mathbf{b}|\cos(\mathbf{a}, \mathbf{b})$ |
| $(B)$ $(\mathbf{c} \times \mathbf{a}) \times \mathbf{b}$ | $2. (\mathbf{a} \cdot \mathbf{c})\mathbf{b} - (\mathbf{a} \cdot \mathbf{b})\mathbf{c}$ |
| $(C)$ $\mathbf{a} \times (\mathbf{b} \times \mathbf{c})$ | $3. \mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})$ |
| $(D)$ $\mathbf{a} \cdot \mathbf{b}$ | $4. |\mathbf{a}||\mathbf{b}|$ |
| $5. (\mathbf{b} \cdot \mathbf{c})\mathbf{a} - (\mathbf{a} \cdot \mathbf{b})\mathbf{c}$ |
- A$A-3, B-5, C-2, D-1$
- B$A-3, B-2, C-5, D-1$
- C$A-3, B-5, C-5, D-1$
- D$A-3, B-5, C-2, D-4$
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