(B) compound exhibits optical isomerism if it contains at least one chiral carbon atom (a carbon atom bonded to four different groups).In $CH_3CHClBr$

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(B) compound exhibits optical isomerism if it contains at least one chiral carbon atom (a carbon atom bonded to four different groups).In $CH_3CHClBr$,the central carbon atom is bonded to four different groups: $-H$,$-CH_3$,$-Cl$,and $-Br$.Therefore,$CH_3CHClBr$ is a chiral molecule and exhibits optical isomerism.