The total number of chiral molecules formed f | vedclass

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(C) Ozonolysis of the given molecule $P$ involves the cleavage of all $C=C$ double bonds.Upon performing ozonolysis $(O_3, Zn / H_2O)$,the molecule $P

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$2$

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(C) Ozonolysis of the given molecule $P$ involves the cleavage of all $C=C$ double bonds.Upon performing ozonolysis $(O_3, Zn / H_2O)$,the molecule $P$ breaks into several smaller carbonyl compounds.By analyzing the structure of the products formed:$1$. $CH_3CH_2CHO$ (Propanal) - Achiral$2$. $CH_3C(=O)C(OH)(CH_3)C(=O)CH_3$ - Achiral (due to plane of symmetry)$3$. $CH_3C(=O)C(OH)(CH_3)CHO$ - Chiral (contains a chiral center)$4$. $CH_3C(=O)C(OH)(CH_3)C(=O)CH_3$ - Achiral$5$. $CH_3C(=O)C(OH)(CH_3)CHO$ - Chiral$6$. $CH_3C(=O)C(OH)(CH_3)C(=O)CH_3$ - Achiral$7$. $CH_3CHO$ (Ethanal) - AchiralCounting the chiral molecules,we find there are $2$ such molecules.

Column-$(I)$	Column-$(II)$
$(A)$ $C_2H_5-C(CH_3)(OH)-H$	$(p)$ $Cl-C(Br)(I)-H$
$(B)$ $Br-C(Cl)(I)-H$	$(q)$ $OH-C(CH_3)(C_2H_5)-H$
	$(r)$ $H_5C_2-C(OH)(CH_3)-H$
	$(s)$ $Cl-C(I)(Br)-H$

The total number of chiral molecules formed from one molecule of $P$ on complete ozonolysis $(O_3, Zn / H_2O)$ is. . . . . . .

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Find the enantiomers of the structures in Column-$(I)$ from Column-$(II)$.
Column-$(I)$ Column-$(II)$
$(A)$ $C_2H_5-C(CH_3)(OH)-H$ $(p)$ $Cl-C(Br)(I)-H$
$(B)$ $Br-C(Cl)(I)-H$ $(q)$ $OH-C(CH_3)(C_2H_5)-H$
$(r)$ $H_5C_2-C(OH)(CH_3)-H$
$(s)$ $Cl-C(I)(Br)-H$

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