On passing $C$ ampere of electricity through an electrolyte solution for $t$ seconds,$m$ grams of metal are deposited on the cathode. The equivalent weight $E$ of the metal is:
- A$E = \frac{C \times t}{m \times 96500}$
- B$E = \frac{C \times m}{t \times 96500}$
- C$E = \frac{96500 \times m}{C \times t}$
- D$E = \frac{C \times t \times 96500}{m}$
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