On passing electric current in an electrolyte | vedclass

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(A) During electrolysis,the ion with the higher standard reduction potential $(E^0)$ is reduced at the cathode.For $MgCl_2$,the ions present are $Mg^{

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$MgCl_2$

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(A) During electrolysis,the ion with the higher standard reduction potential $(E^0)$ is reduced at the cathode.For $MgCl_2$,the ions present are $Mg^{2+}$ and $H^+$ (from water). The reduction potential of $H^+/H_2$ $(0.00 \ V)$ is higher than that of $Mg^{2+}/Mg$ $(-2.37 \ V)$.Therefore,$H^+$ ions are reduced to $H_2$ gas at the cathode.In the other options ($AuCl_3$,$CuCl_2$,$AgNO_3$),the metal ions ($Au^{3+}$,$Cu^{2+}$,$Ag^+$) have higher reduction potentials than $H^+$,so the respective metals will be deposited at the cathode instead of $H_2$ gas.

On passing electric current in an electrolyte solution,$H_2$ gas is liberated at the cathode. Then the electrolyte could be:

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