The order of decreasing basic strength of hal | vedclass

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Question

(A) The basic strength of an anion is inversely proportional to the acidic strength of its conjugate acid.The conjugate acids of the given halides are

Vedclass · Accepted Answer

$F^{-} > Cl^{-} > Br^{-} > I^{-}$

Vedclass · Answer

(A) The basic strength of an anion is inversely proportional to the acidic strength of its conjugate acid.The conjugate acids of the given halides are $HF$,$HCl$,$HBr$,and $HI$.The acidic strength order of these hydrohalic acids is $HI > HBr > HCl > HF$.Since the acidic strength decreases from $HI$ to $HF$,the basic strength of the corresponding conjugate bases increases in the order $I^{-} Therefore,the order of decreasing basic strength is $F^{-} > Cl^{-} > Br^{-} > I^{-}$.Thus,the correct option is $A$.

Acid	$HF$	$HCl$	$HBr$	$HI$
$K_a$	$7.2 \times 10^{-4}$	$1 \times 10^6$	$1 \times 10^9$	$3 \times 10^{11}$

The order of decreasing basic strength of halides is:

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Acid $HF$ $HCl$ $HBr$ $HI$

$K_a$ $7.2 \times 10^{-4}$ $1 \times 10^6$ $1 \times 10^9$ $3 \times 10^{11}$

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