Out of $o$- and $p$-dibromobenzene,which one has a higher melting point and why?
- A$o$-dibromobenzene due to higher polarity.
- B$p$-dibromobenzene due to its symmetrical structure.
- C$o$-dibromobenzene due to higher intermolecular forces.
- D$p$-dibromobenzene due to higher molecular weight.
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Similar Questions
Which of the following compounds will not undergo Friedel-Craft's reaction easily?
MediumNEET 2013
View SolutionIdentify the product formed from chlorobenzene on heating with conc. $HNO_3$ in the presence of conc. $H_2SO_4$.
The decreasing order of reactivity of the following compounds towards $Na^{\oplus} O^{\ominus} Me$ is:
Difficult
View SolutionAssertion : Friedel-Craft's reaction is used to introduce an alkyl or acyl group in benzene nucleus.
Reason : Benzene is a solvent for the Friedel-Craft's alkylation of bromobenzene.
Reason : Benzene is a solvent for the Friedel-Craft's alkylation of bromobenzene.
DifficultAIIMS 2008
View SolutionMatch the reactants in Column-$I$ with their products in Column-$II$.Column-$I$ (Reactants) Column-$II$ (Products) $(A)$ $p$-Nitrochlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 443 \ K}$ $(i)$ Phenol $(B)$ Chlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 623 \ K, 300 \ atm}$ $(ii)$ $2,4,6$-Trinitrophenol $(C)$ $2,4$-Dinitrochlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 368 \ K}$ $(iii)$ $2,4$-Dinitrophenol $(D)$ $2,4,6$-Trinitrochlorobenzene $\xrightarrow{Warm \ H_2O}$ $(iv)$ $p$-Nitrophenol
| Column-$I$ (Reactants) | Column-$II$ (Products) |
|---|---|
| $(A)$ $p$-Nitrochlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 443 \ K}$ | $(i)$ Phenol |
| $(B)$ Chlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 623 \ K, 300 \ atm}$ | $(ii)$ $2,4,6$-Trinitrophenol |
| $(C)$ $2,4$-Dinitrochlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 368 \ K}$ | $(iii)$ $2,4$-Dinitrophenol |
| $(D)$ $2,4,6$-Trinitrochlorobenzene $\xrightarrow{Warm \ H_2O}$ | $(iv)$ $p$-Nitrophenol |
Difficult
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