Out of 7 consonants and 4 vowels,how many wor | vedclass

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(C) Step $1$: Select $3$ consonants from $7$ consonants. The number of ways is ${ }^{7} C_{3} = \frac{7 	imes 6 	imes 5}{3 	imes 2 	imes 1} = 35$.

Vedclass · Accepted Answer

$25200$

Vedclass · Answer

(C) Step $1$: Select $3$ consonants from $7$ consonants. The number of ways is ${ }^{7} C_{3} = \frac{7 	imes 6 	imes 5}{3 	imes 2 	imes 1} = 35$.Step $2$: Select $2$ vowels from $4$ vowels. The number of ways is ${ }^{4} C_{2} = \frac{4 	imes 3}{2 	imes 1} = 6$.Step $3$: The total number of combinations of $3$ consonants and $2$ vowels is $35 	imes 6 = 210$.Step $4$: Since these $5$ letters (total $3+2$) can be arranged among themselves in $5!$ ways,the total number of words is $210 	imes 5! = 210 	imes 120 = 25200$.

Out of $7$ consonants and $4$ vowels,how many words of $3$ consonants and $2$ vowels can be formed?

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