The oxidation states of H,N,and C in HNC are | vedclass

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Question

(A) In the molecule $HNC$ (hydrogen isocyanide),the electronegativity values are $C > N > H$. Assigning oxidation states based on electronegativity: $

Vedclass · Accepted Answer

$+1, -3, +2$

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(A) In the molecule $HNC$ (hydrogen isocyanide),the electronegativity values are $C > N > H$. Assigning oxidation states based on electronegativity: $H$ is bonded to $N$,so $H$ has an oxidation state of $+1$. $N$ is bonded to $H$ and $C$. Since $N$ is more electronegative than $H$ but less than $C$,the net charge on $N$ is $-3$. $C$ is bonded to $N$ with a triple bond,and since $C$ is more electronegative than $N$,$C$ has an oxidation state of $+2$. Thus,the oxidation states are $H = +1$,$N = -3$,and $C = +2$.

The oxidation states of $H$,$N$,and $C$ in $HNC$ are respectively:

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