Particle A moves along the X-axis with a unif | vedclass

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(B) The velocity of particle $A$ is given by $\vec{v}_A = 10 \hat{i} \ m/s$.The velocity of particle $B$ can be resolved into components. Its magnitud

Vedclass · Accepted Answer

$10 \sqrt{3} \ m/s$ along the $Y$-axis (perpendicular to the $X$-axis)

Vedclass · Answer

(B) The velocity of particle $A$ is given by $\vec{v}_A = 10 \hat{i} \ m/s$.The velocity of particle $B$ can be resolved into components. Its magnitude is $20 \ m/s$ at an angle of $60^{\circ}$ with the $X$-axis:$\vec{v}_B = (20 \cos 60^{\circ}) \hat{i} + (20 \sin 60^{\circ}) \hat{j}$$\vec{v}_B = (20 	imes 0.5) \hat{i} + (20 	imes \frac{\sqrt{3}}{2}) \hat{j} = 10 \hat{i} + 10 \sqrt{3} \hat{j} \ m/s$.The relative velocity of $B$ with respect to $A$ is $\vec{v}_{BA} = \vec{v}_B - \vec{v}_A$.$\vec{v}_{BA} = (10 \hat{i} + 10 \sqrt{3} \hat{j}) - (10 \hat{i}) = 10 \sqrt{3} \hat{j} \ m/s$.This result indicates a velocity of magnitude $10 \sqrt{3} \ m/s$ directed along the positive $Y$-axis, which is perpendicular to the $X$-axis.

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