Perimeter of rectangle PQRS is 40, cm. If PQ | vedclass

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(A) In a rectangle $PQRS$,opposite sides are equal. Therefore,$PQ = RS$ and $QR = PS$.Given the ratio $PQ : QR = 3 : 5$,let $PQ = 3x$ and $QR = 5x$.Si

Vedclass · Accepted Answer

$7.5$

Vedclass · Answer

(A) In a rectangle $PQRS$,opposite sides are equal. Therefore,$PQ = RS$ and $QR = PS$.Given the ratio $PQ : QR = 3 : 5$,let $PQ = 3x$ and $QR = 5x$.Since $PQ = RS$,we have $RS = 3x$.The perimeter of a rectangle is given by the formula $2 	imes (length + width) = 40\, cm$.Substituting the values: $2 	imes (3x + 5x) = 40$.$2 	imes (8x) = 40$.$16x = 40$.$x = 40 / 16 = 2.5$.Now,calculate $RS = 3x = 3 	imes 2.5 = 7.5\, cm$.

Perimeter of rectangle $PQRS$ is $40\, cm$. If $PQ : QR = 3 : 5$,then $RS = \ldots \ldots \ldots \, cm$.

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