The period of sin theta - sqrt{3} cos theta i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) We can rewrite the expression as: $\sin 	heta - \sqrt{3} \cos 	heta = 2 \left( \frac{1}{2} \sin 	heta - \frac{\sqrt{3}}{2} \cos 	heta ight)$

Vedclass · Accepted Answer

$2\pi$

Vedclass · Answer

(D) We can rewrite the expression as: $\sin 	heta - \sqrt{3} \cos 	heta = 2 \left( \frac{1}{2} \sin 	heta - \frac{\sqrt{3}}{2} \cos 	heta ight)$.Using the identity $\sin(A - B) = \sin A \cos B - \cos A \sin B$,we get: $2 \sin \left( 	heta - \frac{\pi}{3} ight)$.The period of $\sin(k	heta)$ is $\frac{2\pi}{|k|}$.Here,$k = 1$,so the period is $\frac{2\pi}{1} = 2\pi$.

The period of $\sin \theta - \sqrt{3} \cos \theta$ is

Similar Questions

The period of $\cos(x + 8x + 27x + \ldots + n^3x)$ is

The period of the function $f(x) = e^{\log(\sin x)} + (\tan x)^3 - \operatorname{cosec}(3x - 5)$ is

The period of the function $\sin \left( \frac{2x}{3} \right) + \sin \left( \frac{3x}{2} \right)$ is (in $\pi$)

The period of $f(x) = \cos \left(\frac{x}{3}\right) + \sin \left(\frac{x}{2}\right)$ is (in $\pi$)

If $f(x)$ is an odd periodic function with period $1$,then $f(2)$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module