Phenol reacts with CHCl_3 and NaOH (at 340 K | vedclass

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Question

(B) The reaction of phenol with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$ at $340 \ K$ is known as the Reimer-Tiemann

Vedclass · Accepted Answer

Salicylaldehyde

Vedclass · Answer

(B) The reaction of phenol with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$ at $340 \ K$ is known as the Reimer-Tiemann reaction.In this reaction,a formyl group $(-CHO)$ is introduced at the ortho position of the benzene ring of phenol.The product formed is $2$-hydroxybenzaldehyde,which is commonly known as Salicylaldehyde.The chemical equation is:$C_6H_5OH + CHCl_3 + 3NaOH \rightarrow C_6H_4(OH)(CHO) + 3NaCl + 2H_2O$Thus,the correct option is $(B)$.

Phenol reacts with $CHCl_3$ and $NaOH$ (at $340 \ K$) to give

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