When phenol is treated with chloroform in the | vedclass

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Question

(D) The reaction described is the Reimer-Tiemann reaction.In this reaction,phenol reacts with chloroform $(CHCl_3)$ in the presence of an aqueous base

Vedclass · Accepted Answer

$2$-Hydroxybenzaldehyde

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(D) The reaction described is the Reimer-Tiemann reaction.In this reaction,phenol reacts with chloroform $(CHCl_3)$ in the presence of an aqueous base like sodium hydroxide $(NaOH)$ to form an intermediate,which upon acidic hydrolysis yields $2$-hydroxybenzaldehyde (also known as salicylaldehyde) as the major product.The chemical equation is:$C_6H_5OH + CHCl_3 + 3NaOH \rightarrow C_6H_4(OH)(CHO) + 3NaCl + 2H_2O$

When phenol is treated with chloroform in the presence of sodium hydroxide,followed by hydrolysis in the presence of an acid,the product formed is:

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