Plot the point $P(-6, 2)$ and from it draw $PM$ and $PN$ as perpendiculars to the $x$-axis and $y$-axis,respectively. Write the coordinates of the points $M$ and $N$.
(N/A) $1$. The point $P(-6, 2)$ is located in the second quadrant where the $x$-coordinate is $-6$ and the $y$-coordinate is $2$.
$2$. $A$ perpendicular $PM$ is drawn from $P$ to the $x$-axis. Since $M$ lies on the $x$-axis,its $y$-coordinate is $0$. The $x$-coordinate remains the same as $P$,which is $-6$. Thus,the coordinates of $M$ are $(-6, 0)$.
$3$. $A$ perpendicular $PN$ is drawn from $P$ to the $y$-axis. Since $N$ lies on the $y$-axis,its $x$-coordinate is $0$. The $y$-coordinate remains the same as $P$,which is $2$. Thus,the coordinates of $N$ are $(0, 2)$.
$2$. $A$ perpendicular $PM$ is drawn from $P$ to the $x$-axis. Since $M$ lies on the $x$-axis,its $y$-coordinate is $0$. The $x$-coordinate remains the same as $P$,which is $-6$. Thus,the coordinates of $M$ are $(-6, 0)$.
$3$. $A$ perpendicular $PN$ is drawn from $P$ to the $y$-axis. Since $N$ lies on the $y$-axis,its $x$-coordinate is $0$. The $y$-coordinate remains the same as $P$,which is $2$. Thus,the coordinates of $N$ are $(0, 2)$.
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