Point (2.8, 4.9) lies in the ldots ldots quad | vedclass

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(D) In the Cartesian plane,the coordinates of a point are represented as $(x, y)$.For the first quadrant,both $x > 0$ and $y > 0$.For the second quadr

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(D) In the Cartesian plane,the coordinates of a point are represented as $(x, y)$.For the first quadrant,both $x > 0$ and $y > 0$.For the second quadrant,$x  0$.For the third quadrant,both $x For the fourth quadrant,$x > 0$ and $y Given the point $(2.8, 4.9)$,we observe that $x = 2.8$ (which is $> 0$) and $y = 4.9$ (which is $> 0$).Since both coordinates are positive,the point $(2.8, 4.9)$ lies in the first quadrant.

$x$	$2$	$4$	$-3$	$-2$	$3$	$0$
$y$	$4$	$2$	$0$	$5$	$-3$	$0$

Point $(2.8, 4.9)$ lies in the $\ldots \ldots$ quadrant.

Similar Questions

In the figure,$LM$ is a line parallel to the $y$-axis at a distance of $3$ units.
$(i)$ What are the coordinates of the points $P, R,$ and $Q$?
$(ii)$ What is the difference between the abscissa of the points $L$ and $M$?

State the coordinates of the points shown in the figure below. (The scale on both axes is $1 \, cm = 10$ units.)

Plot the points $(x, y)$ given by the following table:
$x$ $2$ $4$ $-3$ $-2$ $3$ $0$
$y$ $4$ $2$ $0$ $5$ $-3$ $0$

The line joining $(5, -3)$ and $(-5, -3)$ is $\ldots \ldots \ldots$

In the figure,the point identified by the coordinates $(-5, 3)$ is:

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