The polarising angle for water is 53^circ 4'. | vedclass

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(C) According to Brewster's law, when light is incident at the polarising angle (also known as Brewster's angle, $	heta_P$), the reflected ray and th

Vedclass · Accepted Answer

$36^\circ 56'$

Vedclass · Answer

(C) According to Brewster's law, when light is incident at the polarising angle (also known as Brewster's angle, $	heta_P$), the reflected ray and the refracted ray are perpendicular to each other.Therefore, the sum of the angle of incidence (which is the polarising angle $	heta_P$) and the angle of refraction $(r)$ is $90^\circ$.Mathematically, $	heta_P + r = 90^\circ$.Given $	heta_P = 53^\circ 4'$, we can find $r$ as:$r = 90^\circ - 53^\circ 4'$.Since $90^\circ = 89^\circ 60'$, we have:$r = 89^\circ 60' - 53^\circ 4' = 36^\circ 56'$.Thus, the angle of refraction is $36^\circ 56'$.

The polarising angle for water is $53^\circ 4'$. If light is incident at this angle on the surface of water and reflected, the angle of refraction is:

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