$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_{a}$ and $\lambda_{g}$ are the wavelengths of light in air and glass respectively,then:

  • A
    $\lambda_g = \lambda_a \cot \theta$
  • B
    $\lambda_a = \lambda_g \tan^2 \theta$
  • C
    $\lambda_g = \lambda_a \tan^2 \theta$
  • D
    $\lambda_a = \lambda_g \cot \theta$

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