The angle of polarisation for a medium is $60^o$. What will be the critical angle for this medium?

The polarising angle for water is $53^\circ 4'$. If light is incident at this angle on the surface of water and reflected, the angle of refraction is:

Let the speed of light in a medium be $V$ and the polarising angle be $i_p$. If $C$ is the speed of light in vacuum,what is the relation between them?

For a given medium,the polarizing angle is $60^{\circ}$. The critical angle for this medium is . . . . . .

$A$ solid glass sphere of refractive index $n=\sqrt{3}$ and radius $R$ contains a spherical air cavity of radius $\frac{R}{2}$,as shown in the figure. $A$ very thin glass layer is present at the point $O$ so that the air cavity (refractive index $n=1$) remains inside the glass sphere. An unpolarized,unidirectional and monochromatic light source $S$ emits a light ray from a point inside the glass sphere towards the periphery of the glass sphere. If the light is reflected from the point $O$ and is fully polarized,then the angle of incidence at the inner surface of the glass sphere is $\theta$. The value of $\sin \theta$ is

Light is incident on a glass surface at a polarizing angle of $57.5^{\circ}$. Then the angle between the incident ray and the refracted ray is: (in $^{\circ}$)