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(B) According to Brewster's Law, when light is incident at the polarizing angle $i_p$, the reflected ray is completely polarized, and the reflected ra

Vedclass · Accepted Answer

$32.3$

Vedclass · Answer

(B) According to Brewster's Law, when light is incident at the polarizing angle $i_p$, the reflected ray is completely polarized, and the reflected ray is perpendicular to the refracted ray.Brewster's Law states: $	an i_p = \frac{\mu_2}{\mu_1} = \frac{\mu_{glass}}{\mu_{air}}$.Given $\mu_{glass} = 1.52$ and $\mu_{air} = 1.00$, we have $	an i_p = 1.52$.From the given data, $i_p = 	an^{-1}(1.52) = 57.7^{\circ}$.At the polarizing angle, the angle of incidence $i_p$ and the angle of refraction $r$ satisfy the relation $i_p + r = 90^{\circ}$.Therefore, $r = 90^{\circ} - i_p = 90^{\circ} - 57.7^{\circ} = 32.3^{\circ}$.Thus, the angle of the refracted beam with respect to the normal is $32.3^{\circ}$.

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