The polarising angle for a transparent medium | vedclass

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(C) According to Brewster's Law,the refractive index $\mu$ of a transparent medium is given by $\mu = 	an 	heta$,where $	heta$ is the polarising an

Vedclass · Accepted Answer

$	heta = \cot^{-1}\left(\frac{V}{c}ight)$

Vedclass · Answer

(C) According to Brewster's Law,the refractive index $\mu$ of a transparent medium is given by $\mu = 	an 	heta$,where $	heta$ is the polarising angle.We also know that the refractive index $\mu$ is defined as the ratio of the speed of light in vacuum $(c)$ to the speed of light in the medium $(V)$:$\mu = \frac{c}{V}$Equating the two expressions for $\mu$:$	an 	heta = \frac{c}{V}$Taking the reciprocal on both sides:$\cot 	heta = \frac{V}{c}$Therefore,the relation between $	heta$ and $V$ is:$	heta = \cot^{-1}\left(\frac{V}{c}ight)$

The polarising angle for a transparent medium is $\theta$ and $V$ is the speed of light in that medium. The relation between $\theta$ and $V$ is (where $c$ is the velocity of light in vacuum):

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