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(C) The average velocity $v_{av}$ is defined as the total displacement divided by the total time interval: $v_{av} = \frac{\Delta x}{\Delta t} = \frac

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$6$

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(C) The average velocity $v_{av}$ is defined as the total displacement divided by the total time interval: $v_{av} = \frac{\Delta x}{\Delta t} = \frac{x_f - x_i}{t_f - t_i}$.For the average velocity to be zero,the total displacement must be zero,which means the final position $x_f$ must be equal to the initial position $x_i$.From the graph,at $t_i = 0 \, s$,the initial position is $x_i = 6 \, m$.We need to find the time $t$ such that the position $x(t) = 6 \, m$.Looking at the graph,the curve intersects the line $x = 6 \, m$ at $t = 0 \, s$ and again at $t = 6 \, s$.Therefore,at $t = 6 \, s$,the displacement is $\Delta x = 6 \, m - 6 \, m = 0 \, m$.Thus,the average velocity is zero at $t = 6 \, s$.

The position-time graph for a particle is shown in the figure. Starting from $t=0$,at what time $t$ (in seconds) is the average velocity zero?

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