The potential energy of an electron present i | vedclass

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Question

(A) The potential energy $(P.E.)$ of an electron in a hydrogen-like species is given by the formula: $P.E. = -\frac{KZe^2}{r}$.For $He^{+}$,the atomic

Vedclass · Accepted Answer

$-\frac{e^2}{2\pi \epsilon_0 r}$

Vedclass · Answer

(A) The potential energy $(P.E.)$ of an electron in a hydrogen-like species is given by the formula: $P.E. = -\frac{KZe^2}{r}$.For $He^{+}$,the atomic number $Z = 2$.Substituting $K = \frac{1}{4\pi \epsilon_0}$ and $Z = 2$ into the formula:$P.E. = -\frac{1}{4\pi \epsilon_0} 	imes \frac{2e^2}{r} = -\frac{2e^2}{4\pi \epsilon_0 r} = -\frac{e^2}{2\pi \epsilon_0 r}$.Therefore,the correct option is $A$.

The potential energy of an electron present in $He^{+}$ is:

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