Power delivered by the source of the circuit becomes maximum,when

The quality factor of an $LCR$ circuit having resistance $(R)$ and inductance $(L)$ at resonance frequency $(\omega)$ is given by:

An ideal resistance $R$,ideal inductance $L$,ideal capacitance $C$,and $AC$ voltmeters $V_{1}, V_{2}, V_{3}$ and $V_{4}$ are connected to an $AC$ source as shown in the figure. At resonance,

In a series resonant $LCR$ circuit,for the power dissipated to become half of the maximum power dissipated,the current amplitude is

For an $L-C-R$ $AC$ circuit,the resonance frequency is $5000 \ Hz$ and the frequencies at half-power points are $4950 \ Hz$ and $5050 \ Hz$. What will be the $Q$-factor?

In a series resonant $LCR$ circuit,the voltage across $R$ is $100 \, V$ and $R = 1 \, k\Omega$ with $C = 2 \, \mu F$. The resonant frequency $\omega$ is $200 \, rad/s$. At resonance,the voltage across $L$ is......$V$.