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(C) The reaction proceeds in three steps: $1$. Friedel-Crafts Acylation: Benzene reacts with butanoyl chloride in the presence of $AlCl_3$ to form but

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$1-$bromo$-4-$butylbenzene

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(C) The reaction proceeds in three steps: $1$. Friedel-Crafts Acylation: Benzene reacts with butanoyl chloride in the presence of $AlCl_3$ to form butyrophenone $(C_6H_5COCH_2CH_2CH_3)$. $2$. Clemmensen Reduction: The carbonyl group of butyrophenone is reduced to a methylene group using $Zn(Hg)$ and $HCl$,yielding butylbenzene $(C_6H_5CH_2CH_2CH_2CH_3)$. $3$. Electrophilic Aromatic Substitution: The butyl group is an ortho/para-directing activator. Due to steric hindrance,the para-substituted product is the major product. Thus,the final product is $1-$bromo$-4-$butylbenzene.

Predict the product of the following reaction sequence:
$1$. Benzene + $CH_3CH_2CH_2COCl / AlCl_3$
$2$. $Zn(Hg), HCl$
$3$. $Br_2, FeBr_3$

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Predict the product of the following reaction sequence: $1$. Benzene + $CH_3CH_2CH_2COCl / AlCl_3$ $2$. $Zn(Hg), HCl$ $3$. $Br_2, FeBr_3$