The product (C) in the following reaction seq | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Reaction with $SO_2Cl_2$ in the presence of $h
u$ (light) is a free radical chlorination. It selectively chlorinates the tertiary carbo

Vedclass · Accepted Answer

Vedclass · Answer

(A) Step $1$: Reaction with $SO_2Cl_2$ in the presence of $h
u$ (light) is a free radical chlorination. It selectively chlorinates the tertiary carbon of the cyclopentyl group attached to the benzene ring to form $(A)$,which is $1-chloro-1-phenylcyclopentane$ derivative.Step $2$: Reaction with $NBS$ ($N$-Bromosuccinimide) is a benzylic bromination. It replaces a hydrogen atom on the methyl group attached to the benzene ring with a bromine atom to form $(B)$,which is $1-chloro-1-(4-(bromomethyl)phenyl)cyclopentane$.Step $3$: Reaction with $KSH$ is a nucleophilic substitution $(S_N2)$ reaction. The $SH^-$ nucleophile attacks the benzylic carbon,replacing the bromine atom to form $(C)$,which is $1-chloro-1-(4-(mercaptomethyl)phenyl)cyclopentane$.

The product $(C)$ in the following reaction sequence is:

Similar Questions

What will be the reduction products of the following reactions:
$CHCl_3 \xrightarrow[Zn/HCl \text{ (alc.)}]{+2H}$
$CHCl_3 \xrightarrow[Zn/HCl \text{ (aq.)}]{+4H}$
$CHCl_3 \xrightarrow[Zn/H_2O]{+6H}$

An alkyl halide may be converted into an alcohol by

In which of the following reactions is the $Saytzeff$ alkene the major product?

Which one is liquid at room temperature?

The reaction of $CH_3CD_2CHBr-CH_2CD_3$ with alc. $KOH$ yields:

Vedclass Test Series

Exam Paper Generator

Online Exam Module