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(B) $1$. The starting material is $3-$bromo$butan-2-$ol. Reaction with $HBr$ replaces the $-OH$ group with $-Br$ to form $2,3-$dibromobutane $(X)$.$2$

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trans $-2-$ butene

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(B) $1$. The starting material is $3-$bromo$butan-2-$ol. Reaction with $HBr$ replaces the $-OH$ group with $-Br$ to form $2,3-$dibromobutane $(X)$.$2$. The reaction of $2,3-$dibromobutane with $NaI$ in acetone is a debromination reaction (Finkelstein-like conditions leading to elimination).$3$. The anti-elimination of the two bromine atoms from the meso or racemic form (depending on the stereochemistry of the starting material) leads to the formation of the more stable alkene.$4$. The major product formed is trans $-2-$ butene due to its higher stability compared to cis $-2-$ butene.

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