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(B) The reaction involves the formation of a cyclic acetal from a $1,3-diol$ and formaldehyde $(HCHO)$ in the presence of an acid catalyst $(TsOH)$.Th

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(B) The reaction involves the formation of a cyclic acetal from a $1,3-diol$ and formaldehyde $(HCHO)$ in the presence of an acid catalyst $(TsOH)$.The starting material is $CH_3-CH(OH)-CH(CH_2Ph)-CH_2OH$.The two hydroxyl groups at the $1$ and $3$ positions relative to each other react with $HCHO$ to form a $1,3-dioxane$ ring.The carbon atom attached to the $CH_3$ group and the carbon atom attached to the $CH_2Ph$ group are part of the ring.Based on the structure,the $CH_3$ group and the $CH_2Ph$ group are on adjacent carbons of the $1,3-dioxane$ ring.Comparing the options,option $(B)$ correctly represents the cyclic acetal formed where the $CH_2Ph$ group is attached to the carbon between the two oxygen-bearing carbons,which matches the connectivity of the starting material.

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