Identify the products (A) and (C) in the foll | vedclass

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(A) $1$. The reaction of $Cyclopentyl-^{14}CN$ with $CH_3MgBr$ followed by acid hydrolysis $(H_3O^\oplus)$ is a standard method to prepare ketones fro

Vedclass · Accepted Answer

$Cyclopentyl-^{14}C(=O)CH_3; CHI_3$

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(A) $1$. The reaction of $Cyclopentyl-^{14}CN$ with $CH_3MgBr$ followed by acid hydrolysis $(H_3O^\oplus)$ is a standard method to prepare ketones from nitriles. The methyl group from the Grignard reagent attacks the nitrile carbon,forming an imine intermediate,which upon hydrolysis yields the ketone: $Cyclopentyl-^{14}C(=O)CH_3$ (Product $A$).$2$. The ketone $(A)$ contains a methyl ketone group $(-C(=O)CH_3)$. When treated with $NaOI$ (which provides $I_2$ and $NaOH$),it undergoes the iodoform reaction.$3$. The iodoform reaction cleaves the methyl group to form iodoform ($CHI_3$,Product $C$) and the corresponding carboxylate salt $(B)$: $Cyclopentyl-^{14}COO^\ominus$.

Identify the products $(A)$ and $(C)$ in the following reaction sequence:
$Cyclopentyl-^{14}CN + CH_3MgBr$ $\xrightarrow{H_3O^\oplus} (A)$ $\xrightarrow{NaOI} (B) + (C)$

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Identify the products $(A)$ and $(C)$ in the following reaction sequence:$Cyclopentyl-^{14}CN + CH_3MgBr$ $\xrightarrow{H_3O^\oplus} (A)$ $\xrightarrow{NaOI} (B) + (C)$