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(A) The reaction sequence is as follows:$1$. Reaction with $	ext{NH}_2	ext{OH}$ converts the ketone ($1$-indanone) into its oxime.$2$. The oxime und

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(A) The reaction sequence is as follows:$1$. Reaction with $	ext{NH}_2	ext{OH}$ converts the ketone ($1$-indanone) into its oxime.$2$. The oxime undergoes $	ext{Beckmann rearrangement}$ in the presence of acid $(	ext{H}^+)$ and heat $(\Delta)$ to form two isomeric cyclic amides (lactams).$3$. Reduction of these amides with $	ext{LiAlH}_4$ yields the corresponding cyclic amines.The final products are $1,2,3,4-	ext{tetrahydroquinoline}$ and $1,2,3,4-	ext{tetrahydroisoquinoline}$.

The products $(A)$ and $(B)$ are formed by the following reaction sequence:
$1$. $\text{NH}_2\text{OH}$
$2$. $\text{H}^+, \Delta$
$3$. $\text{LiAlH}_4$
Identify the products $(A)$ and $(B)$.

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The products $(A)$ and $(B)$ are formed by the following reaction sequence:$1$. $\text{NH}_2\text{OH}$$2$. $\text{H}^+, \Delta$$3$. $\text{LiAlH}_4$Identify the products $(A)$ and $(B)$.