The product $(A)$ is:

Match List-$I$ with List-$II$.
List-$I$ (Reaction):
$A$. Bicyclohexylidene $\rightarrow$ $2$ Cyclohexanone
$B$. Benzene $\rightarrow$ Benzophenone
$C$. Cyclohexanol $\rightarrow$ Cyclohexanone
$D$. Ethylbenzene $\rightarrow$ Potassium benzoate
List-$II$ (Reagents/Condition):
$I$. Benzoyl chloride / Anhydrous $AlCl_3$
$II$. $CrO_3$
$III$. $KMnO_4 / KOH, \Delta$
$IV$. $(i) O_3, (ii) Zn-H_2O$
Choose the correct answer from the options given below:

In the given reaction: $C_6H_5-COCH_3 \xrightarrow[(ii) H^{+}]{(i) Br_2/KOH} CHBr_3 + [X]$,$[X]$ will be:

Consider the following reactions:
$A$ $\xrightarrow[(i) CH_3MgBr]{(ii) H_3O^{+}} B$ $\xrightarrow[573 \text{ K}]{Cu} 2\text{-methyl-2-butene}$
The mass percentage of carbon in $A$ is:

An organic compound neither reacts with neutral ferric chloride solution nor with Fehling solution. It,however,reacts with Grignard reagent and gives a positive iodoform test. The compound is:

$A$ compound $A$ with molecular formula $C_{10}H_{13}Cl$ gives a white precipitate on adding silver nitrate solution. $A$ on reacting with alcoholic $KOH$ gives compound $B$ as the main product. $B$ on ozonolysis gives $C$ and $D$. $C$ gives Cannizzaro reaction but not aldol condensation. $D$ gives aldol condensation but not Cannizzaro reaction. $A$ is: