The product (C) of the following reaction is: | vedclass

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(B) The reaction sequence is as follows:$1$. Aniline reacts with acetic anhydride $(CH_3CO)_2O$ to form acetanilide $(A)$ (protection of the $-NH_2$ g

Vedclass · Accepted Answer

p-Nitroaniline

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(B) The reaction sequence is as follows:$1$. Aniline reacts with acetic anhydride $(CH_3CO)_2O$ to form acetanilide $(A)$ (protection of the $-NH_2$ group).$2$. Acetanilide undergoes nitration with $HNO_3/H_2SO_4$ to give $p$-nitroacetanilide $(B)$ as the major product due to the steric hindrance and the activating effect of the $-NHCOCH_3$ group.$3$. Finally,hydrolysis of $(B)$ with $H^+/H_2O$ removes the acetyl group to yield $p$-nitroaniline $(C)$ as the final product.

The product $(C)$ of the following reaction is:

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