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Question

(A) $1$. The starting material is $1$-methyl-$4$-nitrobenzene. Bromination in the presence of $Fe$ gives $2$-bromo-$1$-methyl-$4$-nitrobenzene $(A)$.$

Vedclass · Accepted Answer

$2-$bromobenzoic acid

Vedclass · Answer

(A) $1$. The starting material is $1$-methyl-$4$-nitrobenzene. Bromination in the presence of $Fe$ gives $2$-bromo-$1$-methyl-$4$-nitrobenzene $(A)$.$2$. Reduction of the nitro group with $Sn/HCl$ converts $(A)$ to $2$-bromo-$4$-methylaniline $(B)$.$3$. Treatment with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ converts the amine group to a diazonium salt $(C)$.$4$. Reduction of the diazonium salt with $H_3PO_2$ removes the $-N_2^+$ group,yielding $2$-bromotoluene $(D)$.$5$. Oxidation of the methyl group with $KMnO_4/HO^-$ followed by acidification yields $2$-bromobenzoic acid $(E)$.

Product $(E)$ is

Similar Questions

An aromatic compound $A$ on treatment with aqueous ammonia and heating forms compound $B$,which on heating with $Br_2$ and $KOH$ forms a compound $C$ of molecular formula $C_6H_7N$. Write the structures and $IUPAC$ names of compounds $A, B$,and $C$.

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Benzyl isocyanide can be obtained from which of the following reactions? Choose the correct answer from the options given below:
$A$. Benzyl bromide + $AgCN$
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$NBS \xrightarrow{KOBr} (A)$. The product $(A)$ is:

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