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(A) The reaction of phenol with $CO_2$ in the presence of $NaOH$ followed by acidification is the Kolbe-Schmitt reaction,which yields salicylic acid (

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(A) The reaction of phenol with $CO_2$ in the presence of $NaOH$ followed by acidification is the Kolbe-Schmitt reaction,which yields salicylic acid ($2$-hydroxybenzoic acid) as product $(A)$.Salicylic acid then reacts with acetic anhydride $(CH_3CO)_2O$ in the presence of an acid catalyst to undergo acetylation of the phenolic $-OH$ group,forming acetylsalicylic acid (aspirin) as product $(B)$.

Product $(A)$ and $(B)$ respectively are $:-$

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