The product of the following reaction is:

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(C) The given reaction is the ozonolysis of $2	ext{-methylprop-1-ene}$ (isobutylene) using $(i) O_3$ followed by $(ii) H_2O/Zn$.Ozonolysis involves t

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$(CH_3)_2C=O 	ext{ and } H_2C=O 	ext{ both}$

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(C) The given reaction is the ozonolysis of $2	ext{-methylprop-1-ene}$ (isobutylene) using $(i) O_3$ followed by $(ii) H_2O/Zn$.Ozonolysis involves the cleavage of the $C=C$ double bond to form carbonyl compounds.The reaction is:$(CH_3)_2C=CH_2 + O_3$ $ightarrow 	ext{ozonide intermediate}$ $\xrightarrow{H_2O/Zn} (CH_3)_2C=O + HCHO$Here,$(CH_3)_2C=O$ is acetone and $HCHO$ is formaldehyde.Therefore,the products are acetone and formaldehyde.

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