The product of this reaction is:

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(B) The reaction involves a nucleophilic substitution where the organolithium compound (bicyclo[$2.2$.$1$]hept$-2-$en$-2-$yllithium) acts as a nucleop

Vedclass · Accepted Answer

$A$ bicyclo[$2.2$.$1$]hept$-2-$ene with a $-CO_2Me$ substituent at the $2$-position.

Vedclass · Answer

(B) The reaction involves a nucleophilic substitution where the organolithium compound (bicyclo[$2.2$.$1$]hept$-2-$en$-2-$yllithium) acts as a nucleophile.It attacks the electrophilic carbonyl carbon of methyl chloroformate $(Cl-CO-OMe)$.The chloride ion $(Cl^-)$ acts as a leaving group.This results in the formation of methyl bicyclo[$2.2$.$1$]hept$-2-$ene$-2-$carboxylate.

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