Propanal on treatment with dilute sodium hydr | vedclass

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Question

(C) $Propanal$ $(CH_3CH_2CHO)$ contains $\alpha$-hydrogens,so it undergoes an aldol condensation reaction in the presence of dilute sodium hydroxide $

Vedclass · Accepted Answer

$CH_3CH_2CH(OH)CH(CH_3)CHO$

Vedclass · Answer

(C) $Propanal$ $(CH_3CH_2CHO)$ contains $\alpha$-hydrogens,so it undergoes an aldol condensation reaction in the presence of dilute sodium hydroxide $(NaOH)$.In this reaction,two molecules of $propanal$ react to form a $\beta$-hydroxy aldehyde.The reaction is as follows:$CH_3CH_2CHO + CH_3CH_2CHO \xrightarrow{dil. NaOH} CH_3CH_2CH(OH)CH(CH_3)CHO$.The product formed is $3-hydroxy-2-methylpentanal$.

$Propanal$ on treatment with dilute sodium hydroxide forms:

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