Propionic acid is subjected to reduction with | vedclass

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Question

(B) The reduction of carboxylic acids with $HI$ in the presence of red phosphorus $(P)$ is a strong reduction method that converts the carboxylic acid

Vedclass · Accepted Answer

Propane

Vedclass · Answer

(B) The reduction of carboxylic acids with $HI$ in the presence of red phosphorus $(P)$ is a strong reduction method that converts the carboxylic acid group $(-COOH)$ into a methyl group $(-CH_3)$.Propionic acid is $CH_3-CH_2-COOH$.Upon reduction,it forms propane $(CH_3-CH_2-CH_3)$.The reaction is: $CH_3-CH_2-COOH + 6HI \xrightarrow{	ext{Red } P} CH_3-CH_2-CH_3 + 2H_2O + 3I_2$.

Propionic acid is subjected to reduction with hydroiodic acid in the presence of a little $P$,the product formed is

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