The radius of isoelectronic species:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) An isoelectronic series is a group of ions that all have the same number of electrons. For example,one isoelectronic series could include $O^{2-},

Vedclass · Accepted Answer

Decreases with the increase of nuclear charge

Vedclass · Answer

(B) An isoelectronic series is a group of ions that all have the same number of electrons. For example,one isoelectronic series could include $O^{2-}, F^{-}, Na^{+}, Mg^{2+}$. These all have $10$ electrons. The number of protons,however,increases as the atomic number increases,which leads to an increase in nuclear charge. As the nuclear charge increases,the effective nuclear charge experienced by the electrons also increases. Consequently,the nucleus attracts the electrons more strongly,pulling them closer. Therefore,the ionic radii of species in an isoelectronic series decrease as the nuclear charge increases.

Ion	Radius $(pm)$
$Q^{a+}$	$53$
$X^{b+}$	$66$
$Y^{c+}$	$40$
$Z^{d+}$	$100$

Similar Questions

Consider the isoelectronic species,$Na^{+}$,$Mg^{2+}$,$F^{-}$,and $O^{2-}$. The correct order of increasing ionic radii is:

Observe the following data.
Ion Radius $(pm)$
$Q^{a+}$ $53$
$X^{b+}$ $66$
$Y^{c+}$ $40$
$Z^{d+}$ $100$
$Q^{a+}, X^{b+}, Y^{c+}, Z^{d+}$ are respectively

Which of the following is the incorrect order of ionic radius?

The ion with the smallest radius among the following is:

Which one of the following species possesses maximum size?

Vedclass Test Series

Exam Paper Generator

Online Exam Module